There is a classical off-by-one error in case when we try to place, for example, 1+1 bytes as hex in the buffer of size 6. The expected result is to get an output truncated, but in the reality we get 6 bytes filed followed by terminating NUL. Change the logic how we fill the output in case of byte dumping into limited space. This will follow the snprintf() behaviour by truncating output even on half bytes.
Unified · Split
| @@ -169,11 +169,15 @@ int hex_dump_to_buffer(const void *buf, size_t len, int rowsize, int groupsize, · 168 unmodified lines | ||
| 169 | 169 | } |
| 170 | 170 | } else { |
| 171 | 171 | for (j = 0; j < len; j++) { |
| 172 | − if (linebuflen < lx + 3) | |
| 172 | + if (linebuflen < lx + 2) | |
| 173 | 173 | goto overflow2; |
| 174 | 174 | ch = ptr[j]; |
| 175 | 175 | linebuf[lx++] = hex_asc_hi(ch); |
| 176 | + if (linebuflen < lx + 2) | |
| 177 | + goto overflow2; | |
| 176 | 178 | linebuf[lx++] = hex_asc_lo(ch); |
| 179 | + if (linebuflen < lx + 2) | |
| 180 | + goto overflow2; | |
| 177 | 181 | linebuf[lx++] = ' '; |
| 178 | 182 | } |
| 179 | 183 | if (j) |