Rely on regex to find the version number, rather than rely on numerical input to be found in a particular input field. Proposed implementation also eliminates the necessity to invoke 'grep' + 'awk'. Tested on: Oracle Linux
Unified · Split
| @@ -94,8 +94,12 @@ awk '/version/{ · 93 unmodified lines | |||
| 94 | substr($0,RSTART,RLENGTH)) | 94 | substr($0,RSTART,RLENGTH)) |
| 95 | }' | 95 | }' |
| 96 | 96 | ||
| 97 | pppd --version 2>&1| grep version | awk \ | 97 | pppd --version 2>&1 | |
| 98 | 'NR==1{print "PPP ", $3}' | 98 | awk '/version/{ |
| 99 | match($0, /[0-9]+([.]?[0-9]+)+/) | ||
| 100 | printf("PPP\t\t\t%s\n", | ||
| 101 | substr($0,RSTART,RLENGTH)) | ||
| 102 | }' | ||
| 99 | 103 | ||
| 100 | isdnctrl 2>&1 | grep version | awk \ | 104 | isdnctrl 2>&1 | grep version | awk \ |
| 101 | 'NR==1{print "isdn4k-utils ", $NF}' | 105 | 'NR==1{print "isdn4k-utils ", $NF}' |