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/* * Copyright (c) 1999, 2008, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation.  Oracle designates this * particular file as subject to the "Classpath" exception as provided * by Oracle in the LICENSE file that accompanied this code. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ package javax.management;  /** * This class is used by the query-building mechanism to represent binary * operations. * @serial include * * @since 1.5 */class BinaryOpValueExp extends QueryEval implements ValueExp {     /* Serial version */    private static final long serialVersionUID = 1216286847881456786L;     /**     * @serial The operator     */    private int op;     /**     * @serial The first value     */    private ValueExp exp1;     /**     * @serial The second value     */    private ValueExp exp2;      /**     * Basic Constructor.     */    public BinaryOpValueExp() {    }     /**     * Creates a new BinaryOpValueExp using operator o applied on v1 and     * v2 values.     */    public BinaryOpValueExp(int o, ValueExp v1, ValueExp v2) {        op   = o;        exp1 = v1;        exp2 = v2;    }      /**     * Returns the operator of the value expression.     */    public int getOperator()  {        return op;    }     /**     * Returns the left value of the value expression.     */    public ValueExp getLeftValue()  {        return exp1;    }     /**     * Returns the right value of the value expression.     */    public ValueExp getRightValue()  {        return exp2;    }     /**     * Applies the BinaryOpValueExp on a MBean.     *     * @param name The name of the MBean on which the BinaryOpValueExp will be applied.     *     * @return  The ValueExp.     *     * @exception BadStringOperationException     * @exception BadBinaryOpValueExpException     * @exception BadAttributeValueExpException     * @exception InvalidApplicationException     */    public ValueExp apply(ObjectName name) throws BadStringOperationException, BadBinaryOpValueExpException,        BadAttributeValueExpException, InvalidApplicationException  {        ValueExp val1 = exp1.apply(name);        ValueExp val2 = exp2.apply(name);        String sval1;        String sval2;        double dval1;        double dval2;        long   lval1;        long   lval2;        boolean numeric = val1 instanceof NumericValueExp;         if (numeric) {            if (((NumericValueExp)val1).isLong()) {                lval1 = ((NumericValueExp)val1).longValue();                lval2 = ((NumericValueExp)val2).longValue();                 switch (op) {                case Query.PLUS:                    return Query.value(lval1 + lval2);                case Query.TIMES:                    return Query.value(lval1 * lval2);                case Query.MINUS:                    return Query.value(lval1 - lval2);                case Query.DIV:                    return Query.value(lval1 / lval2);                }             } else {                dval1 = ((NumericValueExp)val1).doubleValue();                dval2 = ((NumericValueExp)val2).doubleValue();                 switch (op) {                case Query.PLUS:                    return Query.value(dval1 + dval2);                case Query.TIMES:                    return Query.value(dval1 * dval2);                case Query.MINUS:                    return Query.value(dval1 - dval2);                case Query.DIV:                    return Query.value(dval1 / dval2);                }            }        } else {            sval1 = ((StringValueExp)val1).getValue();            sval2 = ((StringValueExp)val2).getValue();             switch (op) {            case Query.PLUS:                return new StringValueExp(sval1 + sval2);            default:                throw new BadStringOperationException(opString());            }        }         throw new BadBinaryOpValueExpException(this);    }     /**     * Returns the string representing the object     */    public String toString()  {        try {            return parens(exp1, true) + " " + opString() + " " + parens(exp2, false);        } catch (BadBinaryOpValueExpException ex) {            return "invalid expression";        }    }     /*     * Add parentheses to the given subexpression if necessary to     * preserve meaning.  Suppose this BinaryOpValueExp is     * Query.times(Query.plus(Query.attr("A"), Query.attr("B")), Query.attr("C")).     * Then the original toString() logic would return A + B * C.     * We check precedences in order to return (A + B) * C, which is the     * meaning of the ValueExp.     *     * We need to add parentheses if the unparenthesized expression would     * be parsed as a different ValueExp from the original.     * We cannot omit parentheses even when mathematically     * the result would be equivalent, because we do not know whether the     * numeric values will be integer or floating-point.  Addition and     * multiplication are associative for integers but not always for     * floating-point.     *     * So the rule is that we omit parentheses if the ValueExp     * is (A op1 B) op2 C and the precedence of op1 is greater than or     * equal to that of op2; or if the ValueExp is A op1 (B op2 C) and     * the precedence of op2 is greater than that of op1.  (There are two     * precedences: that of * and / is greater than that of + and -.)     * The case of (A op1 B) op2 (C op3 D) applies each rule in turn.     *     * The following examples show the rules in action.  On the left,     * the original ValueExp.  On the right, the string representation.     *     * (A + B) + C     A + B + C     * (A * B) + C     A * B + C     * (A + B) * C     (A + B) * C     * (A * B) * C     A * B * C     * A + (B + C)     A + (B + C)     * A + (B * C)     A + B * C     * A * (B + C)     A * (B + C)     * A * (B * C)     A * (B * C)     */    private String parens(ValueExp subexp, boolean left)    throws BadBinaryOpValueExpException {        boolean omit;        if (subexp instanceof BinaryOpValueExp) {            int subop = ((BinaryOpValueExp) subexp).op;            if (left)                omit = (precedence(subop) >= precedence(op));            else                omit = (precedence(subop) > precedence(op));        } else            omit = true;         if (omit)            return subexp.toString();        else            return "(" + subexp + ")";    }     private int precedence(int xop) throws BadBinaryOpValueExpException {        switch (xop) {            case Query.PLUS: case Query.MINUS: return 0;            case Query.TIMES: case Query.DIV: return 1;            default:                throw new BadBinaryOpValueExpException(this);        }    }     private String opString() throws BadBinaryOpValueExpException {        switch (op) {        case Query.PLUS:            return "+";        case Query.TIMES:            return "*";        case Query.MINUS:            return "-";        case Query.DIV:            return "/";        }         throw new BadBinaryOpValueExpException(this);    }     @Deprecated    public void setMBeanServer(MBeanServer s) {        super.setMBeanServer(s);     } }