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| 1 | +/* | |
| 2 | + * Copyright (c) 2000, 2003, Oracle and/or its affiliates. All rights reserved. | |
| 3 | + * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. | |
| 4 | + * | |
| 5 | + * This code is free software; you can redistribute it and/or modify it | |
| 6 | + * under the terms of the GNU General Public License version 2 only, as | |
| 7 | + * published by the Free Software Foundation. Oracle designates this | |
| 8 | + * particular file as subject to the "Classpath" exception as provided | |
| 9 | + * by Oracle in the LICENSE file that accompanied this code. | |
| 10 | + * | |
| 11 | + * This code is distributed in the hope that it will be useful, but WITHOUT | |
| 12 | + * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or | |
| 13 | + * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License | |
| 14 | + * version 2 for more details (a copy is included in the LICENSE file that | |
| 15 | + * accompanied this code). | |
| 16 | + * | |
| 17 | + * You should have received a copy of the GNU General Public License version | |
| 18 | + * 2 along with this work; if not, write to the Free Software Foundation, | |
| 19 | + * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. | |
| 20 | + * | |
| 21 | + * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA | |
| 22 | + * or visit www.oracle.com if you need additional information or have any | |
| 23 | + * questions. | |
| 24 | + */ | |
| 25 | + | |
| 26 | +/* | |
| 27 | + * (C) Copyright IBM Corp. 1999-2000 - All Rights Reserved | |
| 28 | + * | |
| 29 | + * The original version of this source code and documentation is | |
| 30 | + * copyrighted and owned by IBM. These materials are provided | |
| 31 | + * under terms of a License Agreement between IBM and Sun. | |
| 32 | + * This technology is protected by multiple US and International | |
| 33 | + * patents. This notice and attribution to IBM may not be removed. | |
| 34 | + */ | |
| 35 | + | |
| 36 | +package sun.font; | |
| 37 | + | |
| 38 | +import java.text.Bidi; | |
| 39 | + | |
| 40 | +public final class BidiUtils { | |
| 41 | + | |
| 42 | + | |
| 43 | + | |
| 44 | + /** | |
| 45 | + * Return the level of each character into the levels array starting at start. | |
| 46 | + * This is a convenience method for clients who prefer to use an explicit levels | |
| 47 | + * array instead of iterating over the runs. | |
| 48 | + * | |
| 49 | + * @param levels the array to receive the character levels | |
| 50 | + * @param start the starting offset into the the array | |
| 51 | + * @throws IndexOutOfBoundsException if <code>start</code> is less than 0 or | |
| 52 | + * <code>start + getLength()</code> is greater than <code>levels.length</code>. | |
| 53 | + */ | |
| 54 | + public static void getLevels(Bidi bidi, byte[] levels, int start) { | |
| 55 | + int limit = start + bidi.getLength(); | |
| 56 | + | |
| 57 | + if (start < 0 || limit > levels.length) { | |
| 58 | + throw new IndexOutOfBoundsException("levels.length = " + levels.length + | |
| 59 | + " start: " + start + " limit: " + limit); | |
| 60 | + } | |
| 61 | + | |
| 62 | + int runCount = bidi.getRunCount(); | |
| 63 | + int p = start; | |
| 64 | + for (int i = 0; i < runCount; ++i) { | |
| 65 | + int rlimit = start + bidi.getRunLimit(i); | |
| 66 | + byte rlevel = (byte)bidi.getRunLevel(i); | |
| 67 | + | |
| 68 | + while (p < rlimit) { | |
| 69 | + levels[p++] = rlevel; | |
| 70 | + } | |
| 71 | + } | |
| 72 | + } | |
| 73 | + | |
| 74 | + /** | |
| 75 | + * Return an array containing the resolved bidi level of each character, in logical order. | |
| 76 | + * @return an array containing the level of each character, in logical order. | |
| 77 | + */ | |
| 78 | + public static byte[] getLevels(Bidi bidi) { | |
| 79 | + byte[] levels = new byte[bidi.getLength()]; | |
| 80 | + getLevels(bidi, levels, 0); | |
| 81 | + return levels; | |
| 82 | + } | |
| 83 | + | |
| 84 | + static final char NUMLEVELS = 62; | |
| 85 | + | |
| 86 | + /** | |
| 87 | + * Given level data, compute a a visual to logical mapping. | |
| 88 | + * The leftmost (or topmost) character is at visual index zero. The | |
| 89 | + * logical index of the character is derived from the visual index | |
| 90 | + * by the expression <code>li = map[vi];</code>. | |
| 91 | + * @param levels the levels array | |
| 92 | + * @return the mapping array from visual to logical | |
| 93 | + */ | |
| 94 | + public static int[] createVisualToLogicalMap(byte[] levels) { | |
| 95 | + int len = levels.length; | |
| 96 | + int[] mapping = new int[len]; | |
| 97 | + | |
| 98 | + byte lowestOddLevel = (byte)(NUMLEVELS + 1); | |
| 99 | + byte highestLevel = 0; | |
| 100 | + | |
| 101 | + // initialize mapping and levels | |
| 102 | + | |
| 103 | + for (int i = 0; i < len; i++) { | |
| 104 | + mapping[i] = i; | |
| 105 | + | |
| 106 | + byte level = levels[i]; | |
| 107 | + if (level > highestLevel) { | |
| 108 | + highestLevel = level; | |
| 109 | + } | |
| 110 | + | |
| 111 | + if ((level & 0x01) != 0 && level < lowestOddLevel) { | |
| 112 | + lowestOddLevel = level; | |
| 113 | + } | |
| 114 | + } | |
| 115 | + | |
| 116 | + while (highestLevel >= lowestOddLevel) { | |
| 117 | + int i = 0; | |
| 118 | + for (;;) { | |
| 119 | + while (i < len && levels[i] < highestLevel) { | |
| 120 | + i++; | |
| 121 | + } | |
| 122 | + int begin = i++; | |
| 123 | + | |
| 124 | + if (begin == levels.length) { | |
| 125 | + break; // no more runs at this level | |
| 126 | + } | |
| 127 | + | |
| 128 | + while (i < len && levels[i] >= highestLevel) { | |
| 129 | + i++; | |
| 130 | + } | |
| 131 | + int end = i - 1; | |
| 132 | + | |
| 133 | + while (begin < end) { | |
| 134 | + int temp = mapping[begin]; | |
| 135 | + mapping[begin] = mapping[end]; | |
| 136 | + mapping[end] = temp; | |
| 137 | + ++begin; | |
| 138 | + --end; | |
| 139 | + } | |
| 140 | + } | |
| 141 | + | |
| 142 | + --highestLevel; | |
| 143 | + } | |
| 144 | + | |
| 145 | + return mapping; | |
| 146 | + } | |
| 147 | + | |
| 148 | + /** | |
| 149 | + * Return the inverse position map. The source array must map one-to-one (each value | |
| 150 | + * is distinct and the values run from zero to the length of the array minus one). | |
| 151 | + * For example, if <code>values[i] = j</code>, then <code>inverse[j] = i</code>. | |
| 152 | + * @param values the source ordering array | |
| 153 | + * @return the inverse array | |
| 154 | + */ | |
| 155 | + public static int[] createInverseMap(int[] values) { | |
| 156 | + if (values == null) { | |
| 157 | + return null; | |
| 158 | + } | |
| 159 | + | |
| 160 | + int[] result = new int[values.length]; | |
| 161 | + for (int i = 0; i < values.length; i++) { | |
| 162 | + result[values[i]] = i; | |
| 163 | + } | |
| 164 | + | |
| 165 | + return result; | |
| 166 | + } | |
| 167 | + | |
| 168 | + | |
| 169 | + /** | |
| 170 | + * Return an array containing contiguous values from 0 to length | |
| 171 | + * having the same ordering as the source array. If this would be | |
| 172 | + * a canonical ltr ordering, return null. The data in values[] is NOT | |
| 173 | + * required to be a permutation, but elements in values are required | |
| 174 | + * to be distinct. | |
| 175 | + * @param values an array containing the discontiguous values | |
| 176 | + * @return the contiguous values | |
| 177 | + */ | |
| 178 | + public static int[] createContiguousOrder(int[] values) { | |
| 179 | + if (values != null) { | |
| 180 | + return computeContiguousOrder(values, 0, values.length); | |
| 181 | + } | |
| 182 | + | |
| 183 | + return null; | |
| 184 | + } | |
| 185 | + | |
| 186 | + /** | |
| 187 | + * Compute a contiguous order for the range start, limit. | |
| 188 | + */ | |
| 189 | + private static int[] computeContiguousOrder(int[] values, int start, | |
| 190 | + int limit) { | |
| 191 | + | |
| 192 | + int[] result = new int[limit-start]; | |
| 193 | + for (int i=0; i < result.length; i++) { | |
| 194 | + result[i] = i + start; | |
| 195 | + } | |
| 196 | + | |
| 197 | + // now we'll sort result[], with the following comparison: | |
| 198 | + // result[i] lessthan result[j] iff values[result[i]] < values[result[j]] | |
| 199 | + | |
| 200 | + // selection sort for now; use more elaborate sorts if desired | |
| 201 | + for (int i=0; i < result.length-1; i++) { | |
| 202 | + int minIndex = i; | |
| 203 | + int currentValue = values[result[minIndex]]; | |
| 204 | + for (int j=i; j < result.length; j++) { | |
| 205 | + if (values[result[j]] < currentValue) { | |
| 206 | + minIndex = j; | |
| 207 | + currentValue = values[result[minIndex]]; | |
| 208 | + } | |
| 209 | + } | |
| 210 | + int temp = result[i]; | |
| 211 | + result[i] = result[minIndex]; | |
| 212 | + result[minIndex] = temp; | |
| 213 | + } | |
| 214 | + | |
| 215 | + // shift result by start: | |
| 216 | + if (start != 0) { | |
| 217 | + for (int i=0; i < result.length; i++) { | |
| 218 | + result[i] -= start; | |
| 219 | + } | |
| 220 | + } | |
| 221 | + | |
| 222 | + // next, check for canonical order: | |
| 223 | + int k; | |
| 224 | + for (k=0; k < result.length; k++) { | |
| 225 | + if (result[k] != k) { | |
| 226 | + break; | |
| 227 | + } | |
| 228 | + } | |
| 229 | + | |
| 230 | + if (k == result.length) { | |
| 231 | + return null; | |
| 232 | + } | |
| 233 | + | |
| 234 | + // now return inverse of result: | |
| 235 | + return createInverseMap(result); | |
| 236 | + } | |
| 237 | + | |
| 238 | + /** | |
| 239 | + * Return an array containing the data in the values array from start up to limit, | |
| 240 | + * normalized to fall within the range from 0 up to limit - start. | |
| 241 | + * If this would be a canonical ltr ordering, return null. | |
| 242 | + * NOTE: This method assumes that values[] is a logical to visual map | |
| 243 | + * generated from levels[]. | |
| 244 | + * @param values the source mapping | |
| 245 | + * @param levels the levels corresponding to the values | |
| 246 | + * @param start the starting offset in the values and levels arrays | |
| 247 | + * @param limit the limiting offset in the values and levels arrays | |
| 248 | + * @return the normlized map | |
| 249 | + */ | |
| 250 | + public static int[] createNormalizedMap(int[] values, byte[] levels, | |
| 251 | + int start, int limit) { | |
| 252 | + | |
| 253 | + if (values != null) { | |
| 254 | + if (start != 0 || limit != values.length) { | |
| 255 | + // levels optimization | |
| 256 | + boolean copyRange, canonical; | |
| 257 | + byte primaryLevel; | |
| 258 | + | |
| 259 | + if (levels == null) { | |
| 260 | + primaryLevel = (byte) 0x0; | |
| 261 | + copyRange = true; | |
| 262 | + canonical = true; | |
| 263 | + } | |
| 264 | + else { | |
| 265 | + if (levels[start] == levels[limit-1]) { | |
| 266 | + primaryLevel = levels[start]; | |
| 267 | + canonical = (primaryLevel & (byte)0x1) == 0; | |
| 268 | + | |
| 269 | + // scan for levels below primary | |
| 270 | + int i; | |
| 271 | + for (i=start; i < limit; i++) { | |
| 272 | + if (levels[i] < primaryLevel) { | |
| 273 | + break; | |
| 274 | + } | |
| 275 | + if (canonical) { | |
| 276 | + canonical = levels[i] == primaryLevel; | |
| 277 | + } | |
| 278 | + } | |
| 279 | + | |
| 280 | + copyRange = (i == limit); | |
| 281 | + } | |
| 282 | + else { | |
| 283 | + copyRange = false; | |
| 284 | + | |
| 285 | + // these don't matter; but the compiler cares: | |
| 286 | + primaryLevel = (byte) 0x0; | |
| 287 | + canonical = false; | |
| 288 | + } | |
| 289 | + } | |
| 290 | + | |
| 291 | + if (copyRange) { | |
| 292 | + if (canonical) { | |
| 293 | + return null; | |
| 294 | + } | |
| 295 | + | |
| 296 | + int[] result = new int[limit-start]; | |
| 297 | + int baseValue; | |
| 298 | + | |
| 299 | + if ((primaryLevel & (byte)0x1) != 0) { | |
| 300 | + baseValue = values[limit-1]; | |
| 301 | + } else { | |
| 302 | + baseValue = values[start]; | |
| 303 | + } | |
| 304 | + | |
| 305 | + if (baseValue == 0) { | |
| 306 | + System.arraycopy(values, start, result, 0, limit-start); | |
| 307 | + } | |
| 308 | + else { | |
| 309 | + for (int j=0; j < result.length; j++) { | |
| 310 | + result[j] = values[j+start] - baseValue; | |
| 311 | + } | |
| 312 | + } | |
| 313 | + | |
| 314 | + return result; | |
| 315 | + } | |
| 316 | + else { | |
| 317 | + return computeContiguousOrder(values, start, limit); | |
| 318 | + } | |
| 319 | + } | |
| 320 | + else { | |
| 321 | + return values; | |
| 322 | + } | |
| 323 | + } | |
| 324 | + | |
| 325 | + return null; | |
| 326 | + } | |
| 327 | + | |
| 328 | + /** | |
| 329 | + * Reorder the objects in the array into visual order based on their levels. | |
| 330 | + * This is a utility function to use when you have a collection of objects | |
| 331 | + * representing runs of text in logical order, each run containing text | |
| 332 | + * at a single level. The elements in the objects array will be reordered | |
| 333 | + * into visual order assuming each run of text has the level provided | |
| 334 | + * by the corresponding element in the levels array. | |
| 335 | + * @param levels an array representing the bidi level of each object | |
| 336 | + * @param objects the array of objects to be reordered into visual order | |
| 337 | + */ | |
| 338 | + public static void reorderVisually(byte[] levels, Object[] objects) { | |
| 339 | + int len = levels.length; | |
| 340 | + | |
| 341 | + byte lowestOddLevel = (byte)(NUMLEVELS + 1); | |
| 342 | + byte highestLevel = 0; | |
| 343 | + | |
| 344 | + // initialize mapping and levels | |
| 345 | + | |
| 346 | + for (int i = 0; i < len; i++) { | |
| 347 | + byte level = levels[i]; | |
| 348 | + if (level > highestLevel) { | |
| 349 | + highestLevel = level; | |
| 350 | + } | |
| 351 | + | |
| 352 | + if ((level & 0x01) != 0 && level < lowestOddLevel) { | |
| 353 | + lowestOddLevel = level; | |
| 354 | + } | |
| 355 | + } | |
| 356 | + | |
| 357 | + while (highestLevel >= lowestOddLevel) { | |
| 358 | + int i = 0; | |
| 359 | + for (;;) { | |
| 360 | + while (i < len && levels[i] < highestLevel) { | |
| 361 | + i++; | |
| 362 | + } | |
| 363 | + int begin = i++; | |
| 364 | + | |
| 365 | + if (begin == levels.length) { | |
| 366 | + break; // no more runs at this level | |
| 367 | + } | |
| 368 | + | |
| 369 | + while (i < len && levels[i] >= highestLevel) { | |
| 370 | + i++; | |
| 371 | + } | |
| 372 | + int end = i - 1; | |
| 373 | + | |
| 374 | + while (begin < end) { | |
| 375 | + Object temp = objects[begin]; | |
| 376 | + objects[begin] = objects[end]; | |
| 377 | + objects[end] = temp; | |
| 378 | + ++begin; | |
| 379 | + --end; | |
| 380 | + } | |
| 381 | + } | |
| 382 | + | |
| 383 | + --highestLevel; | |
| 384 | + } | |
| 385 | + } | |
| 386 | +} | |