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| 1 | +/* | |
| 2 | + * Copyright (c) 2007, 2011, Oracle and/or its affiliates. All rights reserved. | |
| 3 | + * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. | |
| 4 | + * | |
| 5 | + * This code is free software; you can redistribute it and/or modify it | |
| 6 | + * under the terms of the GNU General Public License version 2 only, as | |
| 7 | + * published by the Free Software Foundation. Oracle designates this | |
| 8 | + * particular file as subject to the "Classpath" exception as provided | |
| 9 | + * by Oracle in the LICENSE file that accompanied this code. | |
| 10 | + * | |
| 11 | + * This code is distributed in the hope that it will be useful, but WITHOUT | |
| 12 | + * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or | |
| 13 | + * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License | |
| 14 | + * version 2 for more details (a copy is included in the LICENSE file that | |
| 15 | + * accompanied this code). | |
| 16 | + * | |
| 17 | + * You should have received a copy of the GNU General Public License version | |
| 18 | + * 2 along with this work; if not, write to the Free Software Foundation, | |
| 19 | + * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. | |
| 20 | + * | |
| 21 | + * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA | |
| 22 | + * or visit www.oracle.com if you need additional information or have any | |
| 23 | + * questions. | |
| 24 | + */ | |
| 25 | + | |
| 26 | +package sun.java2d.pisces; | |
| 27 | + | |
| 28 | +import sun.awt.geom.PathConsumer2D; | |
| 29 | + | |
| 30 | +/** | |
| 31 | + * The <code>Dasher</code> class takes a series of linear commands | |
| 32 | + * (<code>moveTo</code>, <code>lineTo</code>, <code>close</code> and | |
| 33 | + * <code>end</code>) and breaks them into smaller segments according to a | |
| 34 | + * dash pattern array and a starting dash phase. | |
| 35 | + * | |
| 36 | + * <p> Issues: in J2Se, a zero length dash segment as drawn as a very | |
| 37 | + * short dash, whereas Pisces does not draw anything. The PostScript | |
| 38 | + * semantics are unclear. | |
| 39 | + * | |
| 40 | + */ | |
| 41 | +final class Dasher implements sun.awt.geom.PathConsumer2D { | |
| 42 | + | |
| 43 | + private final PathConsumer2D out; | |
| 44 | + private final float[] dash; | |
| 45 | + private final float startPhase; | |
| 46 | + private final boolean startDashOn; | |
| 47 | + private final int startIdx; | |
| 48 | + | |
| 49 | + private boolean starting; | |
| 50 | + private boolean needsMoveTo; | |
| 51 | + | |
| 52 | + private int idx; | |
| 53 | + private boolean dashOn; | |
| 54 | + private float phase; | |
| 55 | + | |
| 56 | + private float sx, sy; | |
| 57 | + private float x0, y0; | |
| 58 | + | |
| 59 | + // temporary storage for the current curve | |
| 60 | + private float[] curCurvepts; | |
| 61 | + | |
| 62 | + /** | |
| 63 | + * Constructs a <code>Dasher</code>. | |
| 64 | + * | |
| 65 | + * @param out an output <code>PathConsumer2D</code>. | |
| 66 | + * @param dash an array of <code>float</code>s containing the dash pattern | |
| 67 | + * @param phase a <code>float</code> containing the dash phase | |
| 68 | + */ | |
| 69 | + public Dasher(PathConsumer2D out, float[] dash, float phase) { | |
| 70 | + if (phase < 0) { | |
| 71 | + throw new IllegalArgumentException("phase < 0 !"); | |
| 72 | + } | |
| 73 | + | |
| 74 | + this.out = out; | |
| 75 | + | |
| 76 | + // Normalize so 0 <= phase < dash[0] | |
| 77 | + int idx = 0; | |
| 78 | + dashOn = true; | |
| 79 | + float d; | |
| 80 | + while (phase >= (d = dash[idx])) { | |
| 81 | + phase -= d; | |
| 82 | + idx = (idx + 1) % dash.length; | |
| 83 | + dashOn = !dashOn; | |
| 84 | + } | |
| 85 | + | |
| 86 | + this.dash = dash; | |
| 87 | + this.startPhase = this.phase = phase; | |
| 88 | + this.startDashOn = dashOn; | |
| 89 | + this.startIdx = idx; | |
| 90 | + this.starting = true; | |
| 91 | + | |
| 92 | + // we need curCurvepts to be able to contain 2 curves because when | |
| 93 | + // dashing curves, we need to subdivide it | |
| 94 | + curCurvepts = new float[8 * 2]; | |
| 95 | + } | |
| 96 | + | |
| 97 | + public void moveTo(float x0, float y0) { | |
| 98 | + if (firstSegidx > 0) { | |
| 99 | + out.moveTo(sx, sy); | |
| 100 | + emitFirstSegments(); | |
| 101 | + } | |
| 102 | + needsMoveTo = true; | |
| 103 | + this.idx = startIdx; | |
| 104 | + this.dashOn = this.startDashOn; | |
| 105 | + this.phase = this.startPhase; | |
| 106 | + this.sx = this.x0 = x0; | |
| 107 | + this.sy = this.y0 = y0; | |
| 108 | + this.starting = true; | |
| 109 | + } | |
| 110 | + | |
| 111 | + private void emitSeg(float[] buf, int off, int type) { | |
| 112 | + switch (type) { | |
| 113 | + case 8: | |
| 114 | + out.curveTo(buf[off+0], buf[off+1], | |
| 115 | + buf[off+2], buf[off+3], | |
| 116 | + buf[off+4], buf[off+5]); | |
| 117 | + break; | |
| 118 | + case 6: | |
| 119 | + out.quadTo(buf[off+0], buf[off+1], | |
| 120 | + buf[off+2], buf[off+3]); | |
| 121 | + break; | |
| 122 | + case 4: | |
| 123 | + out.lineTo(buf[off], buf[off+1]); | |
| 124 | + } | |
| 125 | + } | |
| 126 | + | |
| 127 | + private void emitFirstSegments() { | |
| 128 | + for (int i = 0; i < firstSegidx; ) { | |
| 129 | + emitSeg(firstSegmentsBuffer, i+1, (int)firstSegmentsBuffer[i]); | |
| 130 | + i += (((int)firstSegmentsBuffer[i]) - 1); | |
| 131 | + } | |
| 132 | + firstSegidx = 0; | |
| 133 | + } | |
| 134 | + | |
| 135 | + // We don't emit the first dash right away. If we did, caps would be | |
| 136 | + // drawn on it, but we need joins to be drawn if there's a closePath() | |
| 137 | + // So, we store the path elements that make up the first dash in the | |
| 138 | + // buffer below. | |
| 139 | + private float[] firstSegmentsBuffer = new float[7]; | |
| 140 | + private int firstSegidx = 0; | |
| 141 | + // precondition: pts must be in relative coordinates (relative to x0,y0) | |
| 142 | + // fullCurve is true iff the curve in pts has not been split. | |
| 143 | + private void goTo(float[] pts, int off, final int type) { | |
| 144 | + float x = pts[off + type - 4]; | |
| 145 | + float y = pts[off + type - 3]; | |
| 146 | + if (dashOn) { | |
| 147 | + if (starting) { | |
| 148 | + firstSegmentsBuffer = Helpers.widenArray(firstSegmentsBuffer, | |
| 149 | + firstSegidx, type - 2); | |
| 150 | + firstSegmentsBuffer[firstSegidx++] = type; | |
| 151 | + System.arraycopy(pts, off, firstSegmentsBuffer, firstSegidx, type - 2); | |
| 152 | + firstSegidx += type - 2; | |
| 153 | + } else { | |
| 154 | + if (needsMoveTo) { | |
| 155 | + out.moveTo(x0, y0); | |
| 156 | + needsMoveTo = false; | |
| 157 | + } | |
| 158 | + emitSeg(pts, off, type); | |
| 159 | + } | |
| 160 | + } else { | |
| 161 | + starting = false; | |
| 162 | + needsMoveTo = true; | |
| 163 | + } | |
| 164 | + this.x0 = x; | |
| 165 | + this.y0 = y; | |
| 166 | + } | |
| 167 | + | |
| 168 | + public void lineTo(float x1, float y1) { | |
| 169 | + float dx = x1 - x0; | |
| 170 | + float dy = y1 - y0; | |
| 171 | + | |
| 172 | + float len = (float) Math.sqrt(dx*dx + dy*dy); | |
| 173 | + | |
| 174 | + if (len == 0) { | |
| 175 | + return; | |
| 176 | + } | |
| 177 | + | |
| 178 | + // The scaling factors needed to get the dx and dy of the | |
| 179 | + // transformed dash segments. | |
| 180 | + float cx = dx / len; | |
| 181 | + float cy = dy / len; | |
| 182 | + | |
| 183 | + while (true) { | |
| 184 | + float leftInThisDashSegment = dash[idx] - phase; | |
| 185 | + if (len <= leftInThisDashSegment) { | |
| 186 | + curCurvepts[0] = x1; | |
| 187 | + curCurvepts[1] = y1; | |
| 188 | + goTo(curCurvepts, 0, 4); | |
| 189 | + // Advance phase within current dash segment | |
| 190 | + phase += len; | |
| 191 | + if (len == leftInThisDashSegment) { | |
| 192 | + phase = 0f; | |
| 193 | + idx = (idx + 1) % dash.length; | |
| 194 | + dashOn = !dashOn; | |
| 195 | + } | |
| 196 | + return; | |
| 197 | + } | |
| 198 | + | |
| 199 | + float dashdx = dash[idx] * cx; | |
| 200 | + float dashdy = dash[idx] * cy; | |
| 201 | + if (phase == 0) { | |
| 202 | + curCurvepts[0] = x0 + dashdx; | |
| 203 | + curCurvepts[1] = y0 + dashdy; | |
| 204 | + } else { | |
| 205 | + float p = leftInThisDashSegment / dash[idx]; | |
| 206 | + curCurvepts[0] = x0 + p * dashdx; | |
| 207 | + curCurvepts[1] = y0 + p * dashdy; | |
| 208 | + } | |
| 209 | + | |
| 210 | + goTo(curCurvepts, 0, 4); | |
| 211 | + | |
| 212 | + len -= leftInThisDashSegment; | |
| 213 | + // Advance to next dash segment | |
| 214 | + idx = (idx + 1) % dash.length; | |
| 215 | + dashOn = !dashOn; | |
| 216 | + phase = 0; | |
| 217 | + } | |
| 218 | + } | |
| 219 | + | |
| 220 | + private LengthIterator li = null; | |
| 221 | + | |
| 222 | + // preconditions: curCurvepts must be an array of length at least 2 * type, | |
| 223 | + // that contains the curve we want to dash in the first type elements | |
| 224 | + private void somethingTo(int type) { | |
| 225 | + if (pointCurve(curCurvepts, type)) { | |
| 226 | + return; | |
| 227 | + } | |
| 228 | + if (li == null) { | |
| 229 | + li = new LengthIterator(4, 0.01f); | |
| 230 | + } | |
| 231 | + li.initializeIterationOnCurve(curCurvepts, type); | |
| 232 | + | |
| 233 | + int curCurveoff = 0; // initially the current curve is at curCurvepts[0...type] | |
| 234 | + float lastSplitT = 0; | |
| 235 | + float t = 0; | |
| 236 | + float leftInThisDashSegment = dash[idx] - phase; | |
| 237 | + while ((t = li.next(leftInThisDashSegment)) < 1) { | |
| 238 | + if (t != 0) { | |
| 239 | + Helpers.subdivideAt((t - lastSplitT) / (1 - lastSplitT), | |
| 240 | + curCurvepts, curCurveoff, | |
| 241 | + curCurvepts, 0, | |
| 242 | + curCurvepts, type, type); | |
| 243 | + lastSplitT = t; | |
| 244 | + goTo(curCurvepts, 2, type); | |
| 245 | + curCurveoff = type; | |
| 246 | + } | |
| 247 | + // Advance to next dash segment | |
| 248 | + idx = (idx + 1) % dash.length; | |
| 249 | + dashOn = !dashOn; | |
| 250 | + phase = 0; | |
| 251 | + leftInThisDashSegment = dash[idx]; | |
| 252 | + } | |
| 253 | + goTo(curCurvepts, curCurveoff+2, type); | |
| 254 | + phase += li.lastSegLen(); | |
| 255 | + if (phase >= dash[idx]) { | |
| 256 | + phase = 0f; | |
| 257 | + idx = (idx + 1) % dash.length; | |
| 258 | + dashOn = !dashOn; | |
| 259 | + } | |
| 260 | + } | |
| 261 | + | |
| 262 | + private static boolean pointCurve(float[] curve, int type) { | |
| 263 | + for (int i = 2; i < type; i++) { | |
| 264 | + if (curve[i] != curve[i-2]) { | |
| 265 | + return false; | |
| 266 | + } | |
| 267 | + } | |
| 268 | + return true; | |
| 269 | + } | |
| 270 | + | |
| 271 | + // Objects of this class are used to iterate through curves. They return | |
| 272 | + // t values where the left side of the curve has a specified length. | |
| 273 | + // It does this by subdividing the input curve until a certain error | |
| 274 | + // condition has been met. A recursive subdivision procedure would | |
| 275 | + // return as many as 1<<limit curves, but this is an iterator and we | |
| 276 | + // don't need all the curves all at once, so what we carry out a | |
| 277 | + // lazy inorder traversal of the recursion tree (meaning we only move | |
| 278 | + // through the tree when we need the next subdivided curve). This saves | |
| 279 | + // us a lot of memory because at any one time we only need to store | |
| 280 | + // limit+1 curves - one for each level of the tree + 1. | |
| 281 | + // NOTE: the way we do things here is not enough to traverse a general | |
| 282 | + // tree; however, the trees we are interested in have the property that | |
| 283 | + // every non leaf node has exactly 2 children | |
| 284 | + private static class LengthIterator { | |
| 285 | + private enum Side {LEFT, RIGHT}; | |
| 286 | + // Holds the curves at various levels of the recursion. The root | |
| 287 | + // (i.e. the original curve) is at recCurveStack[0] (but then it | |
| 288 | + // gets subdivided, the left half is put at 1, so most of the time | |
| 289 | + // only the right half of the original curve is at 0) | |
| 290 | + private float[][] recCurveStack; | |
| 291 | + // sides[i] indicates whether the node at level i+1 in the path from | |
| 292 | + // the root to the current leaf is a left or right child of its parent. | |
| 293 | + private Side[] sides; | |
| 294 | + private int curveType; | |
| 295 | + private final int limit; | |
| 296 | + private final float ERR; | |
| 297 | + private final float minTincrement; | |
| 298 | + // lastT and nextT delimit the current leaf. | |
| 299 | + private float nextT; | |
| 300 | + private float lenAtNextT; | |
| 301 | + private float lastT; | |
| 302 | + private float lenAtLastT; | |
| 303 | + private float lenAtLastSplit; | |
| 304 | + private float lastSegLen; | |
| 305 | + // the current level in the recursion tree. 0 is the root. limit | |
| 306 | + // is the deepest possible leaf. | |
| 307 | + private int recLevel; | |
| 308 | + private boolean done; | |
| 309 | + | |
| 310 | + // the lengths of the lines of the control polygon. Only its first | |
| 311 | + // curveType/2 - 1 elements are valid. This is an optimization. See | |
| 312 | + // next(float) for more detail. | |
| 313 | + private float[] curLeafCtrlPolyLengths = new float[3]; | |
| 314 | + | |
| 315 | + public LengthIterator(int reclimit, float err) { | |
| 316 | + this.limit = reclimit; | |
| 317 | + this.minTincrement = 1f / (1 << limit); | |
| 318 | + this.ERR = err; | |
| 319 | + this.recCurveStack = new float[reclimit+1][8]; | |
| 320 | + this.sides = new Side[reclimit]; | |
| 321 | + // if any methods are called without first initializing this object on | |
| 322 | + // a curve, we want it to fail ASAP. | |
| 323 | + this.nextT = Float.MAX_VALUE; | |
| 324 | + this.lenAtNextT = Float.MAX_VALUE; | |
| 325 | + this.lenAtLastSplit = Float.MIN_VALUE; | |
| 326 | + this.recLevel = Integer.MIN_VALUE; | |
| 327 | + this.lastSegLen = Float.MAX_VALUE; | |
| 328 | + this.done = true; | |
| 329 | + } | |
| 330 | + | |
| 331 | + public void initializeIterationOnCurve(float[] pts, int type) { | |
| 332 | + System.arraycopy(pts, 0, recCurveStack[0], 0, type); | |
| 333 | + this.curveType = type; | |
| 334 | + this.recLevel = 0; | |
| 335 | + this.lastT = 0; | |
| 336 | + this.lenAtLastT = 0; | |
| 337 | + this.nextT = 0; | |
| 338 | + this.lenAtNextT = 0; | |
| 339 | + goLeft(); // initializes nextT and lenAtNextT properly | |
| 340 | + this.lenAtLastSplit = 0; | |
| 341 | + if (recLevel > 0) { | |
| 342 | + this.sides[0] = Side.LEFT; | |
| 343 | + this.done = false; | |
| 344 | + } else { | |
| 345 | + // the root of the tree is a leaf so we're done. | |
| 346 | + this.sides[0] = Side.RIGHT; | |
| 347 | + this.done = true; | |
| 348 | + } | |
| 349 | + this.lastSegLen = 0; | |
| 350 | + } | |
| 351 | + | |
| 352 | + // 0 == false, 1 == true, -1 == invalid cached value. | |
| 353 | + private int cachedHaveLowAcceleration = -1; | |
| 354 | + | |
| 355 | + private boolean haveLowAcceleration(float err) { | |
| 356 | + if (cachedHaveLowAcceleration == -1) { | |
| 357 | + final float len1 = curLeafCtrlPolyLengths[0]; | |
| 358 | + final float len2 = curLeafCtrlPolyLengths[1]; | |
| 359 | + // the test below is equivalent to !within(len1/len2, 1, err). | |
| 360 | + // It is using a multiplication instead of a division, so it | |
| 361 | + // should be a bit faster. | |
| 362 | + if (!Helpers.within(len1, len2, err*len2)) { | |
| 363 | + cachedHaveLowAcceleration = 0; | |
| 364 | + return false; | |
| 365 | + } | |
| 366 | + if (curveType == 8) { | |
| 367 | + final float len3 = curLeafCtrlPolyLengths[2]; | |
| 368 | + // if len1 is close to 2 and 2 is close to 3, that probably | |
| 369 | + // means 1 is close to 3 so the second part of this test might | |
| 370 | + // not be needed, but it doesn't hurt to include it. | |
| 371 | + if (!(Helpers.within(len2, len3, err*len3) && | |
| 372 | + Helpers.within(len1, len3, err*len3))) { | |
| 373 | + cachedHaveLowAcceleration = 0; | |
| 374 | + return false; | |
| 375 | + } | |
| 376 | + } | |
| 377 | + cachedHaveLowAcceleration = 1; | |
| 378 | + return true; | |
| 379 | + } | |
| 380 | + | |
| 381 | + return (cachedHaveLowAcceleration == 1); | |
| 382 | + } | |
| 383 | + | |
| 384 | + // we want to avoid allocations/gc so we keep this array so we | |
| 385 | + // can put roots in it, | |
| 386 | + private float[] nextRoots = new float[4]; | |
| 387 | + | |
| 388 | + // caches the coefficients of the current leaf in its flattened | |
| 389 | + // form (see inside next() for what that means). The cache is | |
| 390 | + // invalid when it's third element is negative, since in any | |
| 391 | + // valid flattened curve, this would be >= 0. | |
| 392 | + private float[] flatLeafCoefCache = new float[] {0, 0, -1, 0}; | |
| 393 | + // returns the t value where the remaining curve should be split in | |
| 394 | + // order for the left subdivided curve to have length len. If len | |
| 395 | + // is >= than the length of the uniterated curve, it returns 1. | |
| 396 | + public float next(final float len) { | |
| 397 | + final float targetLength = lenAtLastSplit + len; | |
| 398 | + while(lenAtNextT < targetLength) { | |
| 399 | + if (done) { | |
| 400 | + lastSegLen = lenAtNextT - lenAtLastSplit; | |
| 401 | + return 1; | |
| 402 | + } | |
| 403 | + goToNextLeaf(); | |
| 404 | + } | |
| 405 | + lenAtLastSplit = targetLength; | |
| 406 | + final float leaflen = lenAtNextT - lenAtLastT; | |
| 407 | + float t = (targetLength - lenAtLastT) / leaflen; | |
| 408 | + | |
| 409 | + // cubicRootsInAB is a fairly expensive call, so we just don't do it | |
| 410 | + // if the acceleration in this section of the curve is small enough. | |
| 411 | + if (!haveLowAcceleration(0.05f)) { | |
| 412 | + // We flatten the current leaf along the x axis, so that we're | |
| 413 | + // left with a, b, c which define a 1D Bezier curve. We then | |
| 414 | + // solve this to get the parameter of the original leaf that | |
| 415 | + // gives us the desired length. | |
| 416 | + | |
| 417 | + if (flatLeafCoefCache[2] < 0) { | |
| 418 | + float x = 0+curLeafCtrlPolyLengths[0], | |
| 419 | + y = x+curLeafCtrlPolyLengths[1]; | |
| 420 | + if (curveType == 8) { | |
| 421 | + float z = y + curLeafCtrlPolyLengths[2]; | |
| 422 | + flatLeafCoefCache[0] = 3*(x - y) + z; | |
| 423 | + flatLeafCoefCache[1] = 3*(y - 2*x); | |
| 424 | + flatLeafCoefCache[2] = 3*x; | |
| 425 | + flatLeafCoefCache[3] = -z; | |
| 426 | + } else if (curveType == 6) { | |
| 427 | + flatLeafCoefCache[0] = 0f; | |
| 428 | + flatLeafCoefCache[1] = y - 2*x; | |
| 429 | + flatLeafCoefCache[2] = 2*x; | |
| 430 | + flatLeafCoefCache[3] = -y; | |
| 431 | + } | |
| 432 | + } | |
| 433 | + float a = flatLeafCoefCache[0]; | |
| 434 | + float b = flatLeafCoefCache[1]; | |
| 435 | + float c = flatLeafCoefCache[2]; | |
| 436 | + float d = t*flatLeafCoefCache[3]; | |
| 437 | + | |
| 438 | + // we use cubicRootsInAB here, because we want only roots in 0, 1, | |
| 439 | + // and our quadratic root finder doesn't filter, so it's just a | |
| 440 | + // matter of convenience. | |
| 441 | + int n = Helpers.cubicRootsInAB(a, b, c, d, nextRoots, 0, 0, 1); | |
| 442 | + if (n == 1 && !Float.isNaN(nextRoots[0])) { | |
| 443 | + t = nextRoots[0]; | |
| 444 | + } | |
| 445 | + } | |
| 446 | + // t is relative to the current leaf, so we must make it a valid parameter | |
| 447 | + // of the original curve. | |
| 448 | + t = t * (nextT - lastT) + lastT; | |
| 449 | + if (t >= 1) { | |
| 450 | + t = 1; | |
| 451 | + done = true; | |
| 452 | + } | |
| 453 | + // even if done = true, if we're here, that means targetLength | |
| 454 | + // is equal to, or very, very close to the total length of the | |
| 455 | + // curve, so lastSegLen won't be too high. In cases where len | |
| 456 | + // overshoots the curve, this method will exit in the while | |
| 457 | + // loop, and lastSegLen will still be set to the right value. | |
| 458 | + lastSegLen = len; | |
| 459 | + return t; | |
| 460 | + } | |
| 461 | + | |
| 462 | + public float lastSegLen() { | |
| 463 | + return lastSegLen; | |
| 464 | + } | |
| 465 | + | |
| 466 | + // go to the next leaf (in an inorder traversal) in the recursion tree | |
| 467 | + // preconditions: must be on a leaf, and that leaf must not be the root. | |
| 468 | + private void goToNextLeaf() { | |
| 469 | + // We must go to the first ancestor node that has an unvisited | |
| 470 | + // right child. | |
| 471 | + recLevel--; | |
| 472 | + while(sides[recLevel] == Side.RIGHT) { | |
| 473 | + if (recLevel == 0) { | |
| 474 | + done = true; | |
| 475 | + return; | |
| 476 | + } | |
| 477 | + recLevel--; | |
| 478 | + } | |
| 479 | + | |
| 480 | + sides[recLevel] = Side.RIGHT; | |
| 481 | + System.arraycopy(recCurveStack[recLevel], 0, recCurveStack[recLevel+1], 0, curveType); | |
| 482 | + recLevel++; | |
| 483 | + goLeft(); | |
| 484 | + } | |
| 485 | + | |
| 486 | + // go to the leftmost node from the current node. Return its length. | |
| 487 | + private void goLeft() { | |
| 488 | + float len = onLeaf(); | |
| 489 | + if (len >= 0) { | |
| 490 | + lastT = nextT; | |
| 491 | + lenAtLastT = lenAtNextT; | |
| 492 | + nextT += (1 << (limit - recLevel)) * minTincrement; | |
| 493 | + lenAtNextT += len; | |
| 494 | + // invalidate caches | |
| 495 | + flatLeafCoefCache[2] = -1; | |
| 496 | + cachedHaveLowAcceleration = -1; | |
| 497 | + } else { | |
| 498 | + Helpers.subdivide(recCurveStack[recLevel], 0, | |
| 499 | + recCurveStack[recLevel+1], 0, | |
| 500 | + recCurveStack[recLevel], 0, curveType); | |
| 501 | + sides[recLevel] = Side.LEFT; | |
| 502 | + recLevel++; | |
| 503 | + goLeft(); | |
| 504 | + } | |
| 505 | + } | |
| 506 | + | |
| 507 | + // this is a bit of a hack. It returns -1 if we're not on a leaf, and | |
| 508 | + // the length of the leaf if we are on a leaf. | |
| 509 | + private float onLeaf() { | |
| 510 | + float[] curve = recCurveStack[recLevel]; | |
| 511 | + float polyLen = 0; | |
| 512 | + | |
| 513 | + float x0 = curve[0], y0 = curve[1]; | |
| 514 | + for (int i = 2; i < curveType; i += 2) { | |
| 515 | + final float x1 = curve[i], y1 = curve[i+1]; | |
| 516 | + final float len = Helpers.linelen(x0, y0, x1, y1); | |
| 517 | + polyLen += len; | |
| 518 | + curLeafCtrlPolyLengths[i/2 - 1] = len; | |
| 519 | + x0 = x1; | |
| 520 | + y0 = y1; | |
| 521 | + } | |
| 522 | + | |
| 523 | + final float lineLen = Helpers.linelen(curve[0], curve[1], curve[curveType-2], curve[curveType-1]); | |
| 524 | + if (polyLen - lineLen < ERR || recLevel == limit) { | |
| 525 | + return (polyLen + lineLen)/2; | |
| 526 | + } | |
| 527 | + return -1; | |
| 528 | + } | |
| 529 | + } | |
| 530 | + | |
| 531 | + @Override | |
| 532 | + public void curveTo(float x1, float y1, | |
| 533 | + float x2, float y2, | |
| 534 | + float x3, float y3) | |
| 535 | + { | |
| 536 | + curCurvepts[0] = x0; curCurvepts[1] = y0; | |
| 537 | + curCurvepts[2] = x1; curCurvepts[3] = y1; | |
| 538 | + curCurvepts[4] = x2; curCurvepts[5] = y2; | |
| 539 | + curCurvepts[6] = x3; curCurvepts[7] = y3; | |
| 540 | + somethingTo(8); | |
| 541 | + } | |
| 542 | + | |
| 543 | + @Override | |
| 544 | + public void quadTo(float x1, float y1, float x2, float y2) { | |
| 545 | + curCurvepts[0] = x0; curCurvepts[1] = y0; | |
| 546 | + curCurvepts[2] = x1; curCurvepts[3] = y1; | |
| 547 | + curCurvepts[4] = x2; curCurvepts[5] = y2; | |
| 548 | + somethingTo(6); | |
| 549 | + } | |
| 550 | + | |
| 551 | + public void closePath() { | |
| 552 | + lineTo(sx, sy); | |
| 553 | + if (firstSegidx > 0) { | |
| 554 | + if (!dashOn || needsMoveTo) { | |
| 555 | + out.moveTo(sx, sy); | |
| 556 | + } | |
| 557 | + emitFirstSegments(); | |
| 558 | + } | |
| 559 | + moveTo(sx, sy); | |
| 560 | + } | |
| 561 | + | |
| 562 | + public void pathDone() { | |
| 563 | + if (firstSegidx > 0) { | |
| 564 | + out.moveTo(sx, sy); | |
| 565 | + emitFirstSegments(); | |
| 566 | + } | |
| 567 | + out.pathDone(); | |
| 568 | + } | |
| 569 | + | |
| 570 | + @Override | |
| 571 | + public long getNativeConsumer() { | |
| 572 | + throw new InternalError("Dasher does not use a native consumer"); | |
| 573 | + } | |
| 574 | +} | |
| 575 | + | |