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| 1 | +/* | |
| 2 | + * Copyright (c) 1997, 2003, Oracle and/or its affiliates. All rights reserved. | |
| 3 | + * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. | |
| 4 | + * | |
| 5 | + * This code is free software; you can redistribute it and/or modify it | |
| 6 | + * under the terms of the GNU General Public License version 2 only, as | |
| 7 | + * published by the Free Software Foundation. Oracle designates this | |
| 8 | + * particular file as subject to the "Classpath" exception as provided | |
| 9 | + * by Oracle in the LICENSE file that accompanied this code. | |
| 10 | + * | |
| 11 | + * This code is distributed in the hope that it will be useful, but WITHOUT | |
| 12 | + * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or | |
| 13 | + * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License | |
| 14 | + * version 2 for more details (a copy is included in the LICENSE file that | |
| 15 | + * accompanied this code). | |
| 16 | + * | |
| 17 | + * You should have received a copy of the GNU General Public License version | |
| 18 | + * 2 along with this work; if not, write to the Free Software Foundation, | |
| 19 | + * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. | |
| 20 | + * | |
| 21 | + * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA | |
| 22 | + * or visit www.oracle.com if you need additional information or have any | |
| 23 | + * questions. | |
| 24 | + */ | |
| 25 | + | |
| 26 | +package java.awt.geom; | |
| 27 | + | |
| 28 | +import java.util.*; | |
| 29 | + | |
| 30 | +/** | |
| 31 | + * A utility class to iterate over the path segments of an arc | |
| 32 | + * through the PathIterator interface. | |
| 33 | + * | |
| 34 | + * @author Jim Graham | |
| 35 | + */ | |
| 36 | +class ArcIterator implements PathIterator { | |
| 37 | + double x, y, w, h, angStRad, increment, cv; | |
| 38 | + AffineTransform affine; | |
| 39 | + int index; | |
| 40 | + int arcSegs; | |
| 41 | + int lineSegs; | |
| 42 | + | |
| 43 | + ArcIterator(Arc2D a, AffineTransform at) { | |
| 44 | + this.w = a.getWidth() / 2; | |
| 45 | + this.h = a.getHeight() / 2; | |
| 46 | + this.x = a.getX() + w; | |
| 47 | + this.y = a.getY() + h; | |
| 48 | + this.angStRad = -Math.toRadians(a.getAngleStart()); | |
| 49 | + this.affine = at; | |
| 50 | + double ext = -a.getAngleExtent(); | |
| 51 | + if (ext >= 360.0 || ext <= -360) { | |
| 52 | + arcSegs = 4; | |
| 53 | + this.increment = Math.PI / 2; | |
| 54 | + // btan(Math.PI / 2); | |
| 55 | + this.cv = 0.5522847498307933; | |
| 56 | + if (ext < 0) { | |
| 57 | + increment = -increment; | |
| 58 | + cv = -cv; | |
| 59 | + } | |
| 60 | + } else { | |
| 61 | + arcSegs = (int) Math.ceil(Math.abs(ext) / 90.0); | |
| 62 | + this.increment = Math.toRadians(ext / arcSegs); | |
| 63 | + this.cv = btan(increment); | |
| 64 | + if (cv == 0) { | |
| 65 | + arcSegs = 0; | |
| 66 | + } | |
| 67 | + } | |
| 68 | + switch (a.getArcType()) { | |
| 69 | + case Arc2D.OPEN: | |
| 70 | + lineSegs = 0; | |
| 71 | + break; | |
| 72 | + case Arc2D.CHORD: | |
| 73 | + lineSegs = 1; | |
| 74 | + break; | |
| 75 | + case Arc2D.PIE: | |
| 76 | + lineSegs = 2; | |
| 77 | + break; | |
| 78 | + } | |
| 79 | + if (w < 0 || h < 0) { | |
| 80 | + arcSegs = lineSegs = -1; | |
| 81 | + } | |
| 82 | + } | |
| 83 | + | |
| 84 | + /** | |
| 85 | + * Return the winding rule for determining the insideness of the | |
| 86 | + * path. | |
| 87 | + * @see #WIND_EVEN_ODD | |
| 88 | + * @see #WIND_NON_ZERO | |
| 89 | + */ | |
| 90 | + public int getWindingRule() { | |
| 91 | + return WIND_NON_ZERO; | |
| 92 | + } | |
| 93 | + | |
| 94 | + /** | |
| 95 | + * Tests if there are more points to read. | |
| 96 | + * @return true if there are more points to read | |
| 97 | + */ | |
| 98 | + public boolean isDone() { | |
| 99 | + return index > arcSegs + lineSegs; | |
| 100 | + } | |
| 101 | + | |
| 102 | + /** | |
| 103 | + * Moves the iterator to the next segment of the path forwards | |
| 104 | + * along the primary direction of traversal as long as there are | |
| 105 | + * more points in that direction. | |
| 106 | + */ | |
| 107 | + public void next() { | |
| 108 | + index++; | |
| 109 | + } | |
| 110 | + | |
| 111 | + /* | |
| 112 | + * btan computes the length (k) of the control segments at | |
| 113 | + * the beginning and end of a cubic bezier that approximates | |
| 114 | + * a segment of an arc with extent less than or equal to | |
| 115 | + * 90 degrees. This length (k) will be used to generate the | |
| 116 | + * 2 bezier control points for such a segment. | |
| 117 | + * | |
| 118 | + * Assumptions: | |
| 119 | + * a) arc is centered on 0,0 with radius of 1.0 | |
| 120 | + * b) arc extent is less than 90 degrees | |
| 121 | + * c) control points should preserve tangent | |
| 122 | + * d) control segments should have equal length | |
| 123 | + * | |
| 124 | + * Initial data: | |
| 125 | + * start angle: ang1 | |
| 126 | + * end angle: ang2 = ang1 + extent | |
| 127 | + * start point: P1 = (x1, y1) = (cos(ang1), sin(ang1)) | |
| 128 | + * end point: P4 = (x4, y4) = (cos(ang2), sin(ang2)) | |
| 129 | + * | |
| 130 | + * Control points: | |
| 131 | + * P2 = (x2, y2) | |
| 132 | + * | x2 = x1 - k * sin(ang1) = cos(ang1) - k * sin(ang1) | |
| 133 | + * | y2 = y1 + k * cos(ang1) = sin(ang1) + k * cos(ang1) | |
| 134 | + * | |
| 135 | + * P3 = (x3, y3) | |
| 136 | + * | x3 = x4 + k * sin(ang2) = cos(ang2) + k * sin(ang2) | |
| 137 | + * | y3 = y4 - k * cos(ang2) = sin(ang2) - k * cos(ang2) | |
| 138 | + * | |
| 139 | + * The formula for this length (k) can be found using the | |
| 140 | + * following derivations: | |
| 141 | + * | |
| 142 | + * Midpoints: | |
| 143 | + * a) bezier (t = 1/2) | |
| 144 | + * bPm = P1 * (1-t)^3 + | |
| 145 | + * 3 * P2 * t * (1-t)^2 + | |
| 146 | + * 3 * P3 * t^2 * (1-t) + | |
| 147 | + * P4 * t^3 = | |
| 148 | + * = (P1 + 3P2 + 3P3 + P4)/8 | |
| 149 | + * | |
| 150 | + * b) arc | |
| 151 | + * aPm = (cos((ang1 + ang2)/2), sin((ang1 + ang2)/2)) | |
| 152 | + * | |
| 153 | + * Let angb = (ang2 - ang1)/2; angb is half of the angle | |
| 154 | + * between ang1 and ang2. | |
| 155 | + * | |
| 156 | + * Solve the equation bPm == aPm | |
| 157 | + * | |
| 158 | + * a) For xm coord: | |
| 159 | + * x1 + 3*x2 + 3*x3 + x4 = 8*cos((ang1 + ang2)/2) | |
| 160 | + * | |
| 161 | + * cos(ang1) + 3*cos(ang1) - 3*k*sin(ang1) + | |
| 162 | + * 3*cos(ang2) + 3*k*sin(ang2) + cos(ang2) = | |
| 163 | + * = 8*cos((ang1 + ang2)/2) | |
| 164 | + * | |
| 165 | + * 4*cos(ang1) + 4*cos(ang2) + 3*k*(sin(ang2) - sin(ang1)) = | |
| 166 | + * = 8*cos((ang1 + ang2)/2) | |
| 167 | + * | |
| 168 | + * 8*cos((ang1 + ang2)/2)*cos((ang2 - ang1)/2) + | |
| 169 | + * 6*k*sin((ang2 - ang1)/2)*cos((ang1 + ang2)/2) = | |
| 170 | + * = 8*cos((ang1 + ang2)/2) | |
| 171 | + * | |
| 172 | + * 4*cos(angb) + 3*k*sin(angb) = 4 | |
| 173 | + * | |
| 174 | + * k = 4 / 3 * (1 - cos(angb)) / sin(angb) | |
| 175 | + * | |
| 176 | + * b) For ym coord we derive the same formula. | |
| 177 | + * | |
| 178 | + * Since this formula can generate "NaN" values for small | |
| 179 | + * angles, we will derive a safer form that does not involve | |
| 180 | + * dividing by very small values: | |
| 181 | + * (1 - cos(angb)) / sin(angb) = | |
| 182 | + * = (1 - cos(angb))*(1 + cos(angb)) / sin(angb)*(1 + cos(angb)) = | |
| 183 | + * = (1 - cos(angb)^2) / sin(angb)*(1 + cos(angb)) = | |
| 184 | + * = sin(angb)^2 / sin(angb)*(1 + cos(angb)) = | |
| 185 | + * = sin(angb) / (1 + cos(angb)) | |
| 186 | + * | |
| 187 | + */ | |
| 188 | + private static double btan(double increment) { | |
| 189 | + increment /= 2.0; | |
| 190 | + return 4.0 / 3.0 * Math.sin(increment) / (1.0 + Math.cos(increment)); | |
| 191 | + } | |
| 192 | + | |
| 193 | + /** | |
| 194 | + * Returns the coordinates and type of the current path segment in | |
| 195 | + * the iteration. | |
| 196 | + * The return value is the path segment type: | |
| 197 | + * SEG_MOVETO, SEG_LINETO, SEG_QUADTO, SEG_CUBICTO, or SEG_CLOSE. | |
| 198 | + * A float array of length 6 must be passed in and may be used to | |
| 199 | + * store the coordinates of the point(s). | |
| 200 | + * Each point is stored as a pair of float x,y coordinates. | |
| 201 | + * SEG_MOVETO and SEG_LINETO types will return one point, | |
| 202 | + * SEG_QUADTO will return two points, | |
| 203 | + * SEG_CUBICTO will return 3 points | |
| 204 | + * and SEG_CLOSE will not return any points. | |
| 205 | + * @see #SEG_MOVETO | |
| 206 | + * @see #SEG_LINETO | |
| 207 | + * @see #SEG_QUADTO | |
| 208 | + * @see #SEG_CUBICTO | |
| 209 | + * @see #SEG_CLOSE | |
| 210 | + */ | |
| 211 | + public int currentSegment(float[] coords) { | |
| 212 | + if (isDone()) { | |
| 213 | + throw new NoSuchElementException("arc iterator out of bounds"); | |
| 214 | + } | |
| 215 | + double angle = angStRad; | |
| 216 | + if (index == 0) { | |
| 217 | + coords[0] = (float) (x + Math.cos(angle) * w); | |
| 218 | + coords[1] = (float) (y + Math.sin(angle) * h); | |
| 219 | + if (affine != null) { | |
| 220 | + affine.transform(coords, 0, coords, 0, 1); | |
| 221 | + } | |
| 222 | + return SEG_MOVETO; | |
| 223 | + } | |
| 224 | + if (index > arcSegs) { | |
| 225 | + if (index == arcSegs + lineSegs) { | |
| 226 | + return SEG_CLOSE; | |
| 227 | + } | |
| 228 | + coords[0] = (float) x; | |
| 229 | + coords[1] = (float) y; | |
| 230 | + if (affine != null) { | |
| 231 | + affine.transform(coords, 0, coords, 0, 1); | |
| 232 | + } | |
| 233 | + return SEG_LINETO; | |
| 234 | + } | |
| 235 | + angle += increment * (index - 1); | |
| 236 | + double relx = Math.cos(angle); | |
| 237 | + double rely = Math.sin(angle); | |
| 238 | + coords[0] = (float) (x + (relx - cv * rely) * w); | |
| 239 | + coords[1] = (float) (y + (rely + cv * relx) * h); | |
| 240 | + angle += increment; | |
| 241 | + relx = Math.cos(angle); | |
| 242 | + rely = Math.sin(angle); | |
| 243 | + coords[2] = (float) (x + (relx + cv * rely) * w); | |
| 244 | + coords[3] = (float) (y + (rely - cv * relx) * h); | |
| 245 | + coords[4] = (float) (x + relx * w); | |
| 246 | + coords[5] = (float) (y + rely * h); | |
| 247 | + if (affine != null) { | |
| 248 | + affine.transform(coords, 0, coords, 0, 3); | |
| 249 | + } | |
| 250 | + return SEG_CUBICTO; | |
| 251 | + } | |
| 252 | + | |
| 253 | + /** | |
| 254 | + * Returns the coordinates and type of the current path segment in | |
| 255 | + * the iteration. | |
| 256 | + * The return value is the path segment type: | |
| 257 | + * SEG_MOVETO, SEG_LINETO, SEG_QUADTO, SEG_CUBICTO, or SEG_CLOSE. | |
| 258 | + * A double array of length 6 must be passed in and may be used to | |
| 259 | + * store the coordinates of the point(s). | |
| 260 | + * Each point is stored as a pair of double x,y coordinates. | |
| 261 | + * SEG_MOVETO and SEG_LINETO types will return one point, | |
| 262 | + * SEG_QUADTO will return two points, | |
| 263 | + * SEG_CUBICTO will return 3 points | |
| 264 | + * and SEG_CLOSE will not return any points. | |
| 265 | + * @see #SEG_MOVETO | |
| 266 | + * @see #SEG_LINETO | |
| 267 | + * @see #SEG_QUADTO | |
| 268 | + * @see #SEG_CUBICTO | |
| 269 | + * @see #SEG_CLOSE | |
| 270 | + */ | |
| 271 | + public int currentSegment(double[] coords) { | |
| 272 | + if (isDone()) { | |
| 273 | + throw new NoSuchElementException("arc iterator out of bounds"); | |
| 274 | + } | |
| 275 | + double angle = angStRad; | |
| 276 | + if (index == 0) { | |
| 277 | + coords[0] = x + Math.cos(angle) * w; | |
| 278 | + coords[1] = y + Math.sin(angle) * h; | |
| 279 | + if (affine != null) { | |
| 280 | + affine.transform(coords, 0, coords, 0, 1); | |
| 281 | + } | |
| 282 | + return SEG_MOVETO; | |
| 283 | + } | |
| 284 | + if (index > arcSegs) { | |
| 285 | + if (index == arcSegs + lineSegs) { | |
| 286 | + return SEG_CLOSE; | |
| 287 | + } | |
| 288 | + coords[0] = x; | |
| 289 | + coords[1] = y; | |
| 290 | + if (affine != null) { | |
| 291 | + affine.transform(coords, 0, coords, 0, 1); | |
| 292 | + } | |
| 293 | + return SEG_LINETO; | |
| 294 | + } | |
| 295 | + angle += increment * (index - 1); | |
| 296 | + double relx = Math.cos(angle); | |
| 297 | + double rely = Math.sin(angle); | |
| 298 | + coords[0] = x + (relx - cv * rely) * w; | |
| 299 | + coords[1] = y + (rely + cv * relx) * h; | |
| 300 | + angle += increment; | |
| 301 | + relx = Math.cos(angle); | |
| 302 | + rely = Math.sin(angle); | |
| 303 | + coords[2] = x + (relx + cv * rely) * w; | |
| 304 | + coords[3] = y + (rely - cv * relx) * h; | |
| 305 | + coords[4] = x + relx * w; | |
| 306 | + coords[5] = y + rely * h; | |
| 307 | + if (affine != null) { | |
| 308 | + affine.transform(coords, 0, coords, 0, 3); | |
| 309 | + } | |
| 310 | + return SEG_CUBICTO; | |
| 311 | + } | |
| 312 | +} | |