Code suppression fixes

See adjusted testcase, a lone break; in a do while loop was incorrectly disabling the exit test.

Michael Matz committed 9 years ago

Commit 7ad2cf81 parent 82942853 files · +40 −0Browse files

Unified · Split

3 files

         skip(TOK_WHILE);
         skip('(');
         gsym(b);
+	if (b)
+	    nocode_wanted = saved_nocode_wanted;
 	gexpr();
 	c = gvtst(0, 0);
 	gsym_addr(c, d);

@@ -26,6 +26,36 @@ static void kb_wait_1(void) · 25 unmodified lines
26	timeout--;	26	timeout--;
27	} while (timeout);	27	} while (timeout);
28	}	28	}
		29
		30	static int global;
		31
		32	static void foo(int i)
		33	{
		34	global+=i;
		35	printf ("g=%d\n", global);
		36	}
		37
		38	static int check(void)
		39	{
		40	printf ("check %d\n", global);
		41	return 1;
		42	}
		43
		44	static void dowhile(void)
		45	{
		46	do {
		47	foo(1);
		48	if (global == 1) {
		49	continue;
		50	} else if (global == 2) {
		51	continue;
		52	}
		53	/* The following break shouldn't disable the check() call,
		54	as it's reachable by the continues above. */
		55	break;
		56	} while (check());
		57	}
		58
29	int main (void)	59	int main (void)
30	{	60	{
31	int i = 1;	61	int i = 1;
@@ -118,5 +148,8 @@ enterloop3: · 86 unmodified lines
118	printf ("error4\n");	148	printf ("error4\n");
119	}	149	}
120	}	150	}
		151
		152	dowhile();
		153
121	return 0;	154	return 0;
122	}	155	}

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