#include <u.h>#include <libc.h> /*The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the firstten natural numbers and the square of the sum is3025 − 385 = 2640. Find the difference between the sum of the squares of the firstone hundred natural numbers and the square of the sum.*/ voidmain(){	u64int sumofsquares = 0;	u64int squareofsum = 0;	u64int difference = 0; 	for(int i = 1; i < 101; ++i){		sumofsquares += pow(i, 2);		squareofsum += i;	}	squareofsum = pow(squareofsum, 2);	difference = squareofsum - sumofsquares; 	print("Difference: %lld\n", difference);	exits(0);}